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Where can I find a free manual solution of Fluid (a) Find the dimensions of CL as follows, CL = FL 1 2 2 ρV A → CL = MLT−2 MLT−2 = =1 (ML−3 )(LT−1 )2 (L2 ) MLT−2 Therefore CL is dimensionless and does not depend on the system of units used. Here is a link. I've no idea. Fluid Mechanics · Fluid Dynamics. Mechanical Engineering. link to get the free Fluid Mechanics Solution Manual by John F. Douglas in PDF?
SOLUTIONS MANUAL Engineering Fluid Mechanics, (b) No adjustment factor is necessary when USCS units are used instead of SI units. (a) Inserting the dimensions of the variables in the given equation yields d2 z dz a bz = c 2 dt dt [ ][ ] [ ] M L L a b[L] = c T L3 T2 [ [ ] M L a b[L] = c 2 2 T L T ρ Therefore, the required dimensions of the parameters a, b, and c are, [ [ [ M M M a= , b= , c= L3 T L3 T2 L2 T2 (b) If ρ∗ , z ∗ , and t∗ are the given variables in nonstandard units, then the conversion factors are: ρ z t = 103 , = 10−3 , = 3600 ∗ ∗ ρ z t∗ 1.3. They are all in PDF format. SOLUTIONS MANUAL A Brief Introduction To Fluid Mechanics, 5th Edition by Donald F. Young, Bruce R. SOLUTIONS MANUAL Advanced Engineering Mathematics 2nd Edition by Michael D. Greenberg
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